Obtain a formula for \(\displaystyle\displaystyle\int\limits_{\frac{1}{2}}^{n}{\frac{{{\left( {{\tan }^{-1}}2x \right)}^{2}}}{1+4{{x}^{2}}}}\mathrm{ d}x\) in terms of \(n\), where \(n>0\).
Hence evaluate \(\displaystyle\displaystyle\int\limits_{\frac{1}{2}}^{\infty }{\frac{{{\left( {{\tan }^{-1}}2x \right)}^{2}}}{1+4{{x}^{2}}}}\mathrm{ d}x\) exactly.[4]
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