2009 TPJC P1 Q11

2009 TPJC P1 Q11

9 marks
Prelims
  1. Given that \(y={{\mathrm{e}}^{{{\tan }^{-1}}x}}\), find \(\frac{\mathrm{d}y}{\mathrm{d}x}\) and show that \(\left( 1+{{x}^{2}} \right)\frac{{{\mathrm{d}}^{2}}y}{\mathrm{d}{{x}^{2}}}+\left( 2x-1 \right)\frac{\mathrm{d}y}{\mathrm{d}x}=0\). Obtain the Maclaurin series for \({{\mathrm{e}}^{{{\tan }^{-1}}x}}\) up to and including the term in \({{x}^{2}}\).[5]
  2. Expand \({{\left( 1+3x \right)}^{-\frac{1}{2}}}\) in ascending powers of \(x\) up to and including the term in \({{x}^{2}}\).[2]
  3. Using the series that you obtained in (i) and (ii), deduce the equation of the tangent to the curve \(y=\frac{{{\mathrm{e}}^{{{\tan }^{-1}}x}}}{\sqrt{1+3x}}\) at \(x=0\).[2]

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Answer:e^(tan⁻¹x) ≈ 1 + x + ½x²; (1+3x)^(-½) ≈ 1 − 3x/2 + 27x²/8; tangent: y = −½x + 1

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