HCF by Prime Factorisation

HCF by Prime Factorisation

Secondary 1

The numbers \(26000\) and \(13230\), written as the products of their prime factors, are \(26000={{2}^{4}}\times {{5}^{3}}\times 13\) and \(13230=2\times {{3}^{3}}\times 5\times {{7}^{2}}\). Hence, find the greatest whole number that will divide both \(26000\) and \(13230\) exactly.

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Answer:10.

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