Find the radius and coordinates of the centre of the circle ${{x}^{2}}+{{y}^{2}}-8x-4y-5=0$. Given

Question

Find the radius and coordinates of the centre of the circle ${{x}^{2}}+{{y}^{2}}-8x-4y-5=0$. Given that $AB$ is a diameter of this circle, where $A$ is the point $\left( 1,6 \right)$, find the coordinates of the point $B$.

Accepted Answer

(a) Centre $(4,2)$, radius $5$ (b) $B=(7,-2)$

Coordinate Geometry - Finding the Centre and Radius of a Circle

Coordinate Geometry - Finding the Centre and Radius of a Circle

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