Equation of Perpendicular Bisector

Equation of Perpendicular Bisector

The line \(y=x+2\) meets the curve \({{y}^{2}}=8x+4\) at the points \(A\) and \(B\). Find

  1. the coordinates of \(A\) and \(B\).
  2. the equation of the perpendicular bisector of \(AB\).

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Answer:\(\text{(a)}\hspace{0.5em}A=(0,2),\ B=(4,6)\) \(\text{(b)}\hspace{0.5em}y=-x+6\)

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