Exponential and Logarithmic Functions - Equality of Indices

Exponential and Logarithmic Functions - Equality of Indices

Secondary 3
5 marks
  1. Simplify \(\frac{{{4}^{x+2}}-{{2}^{2x+1}}}{{{8}^{x}}\left( {{4}^{1-x}} \right)}\) and express it in the form \(a\left( {{2}^{x-b}} \right)\) where \(a\) and \(b\) are integers.[3]
  2. Hence, solve for \(x\) if \(\frac{{{4}^{x+2}}-{{2}^{2x+1}}}{{{8}^{x}}\left( {{4}^{1-x}} \right)}=15\).[2]

Solution:

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Answer:(a) \(7(2^{x-1})\), so \(a=7\), \(b=1\). (b) \(x=1+\dfrac{\ln\dfrac{15}{7}}{\ln2}\approx2.10\).

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