Exponential and Logarithmic Functions - Equality of Indices
Exponential and Logarithmic Functions - Equality of Indices
Secondary 3
- Solve \({{2}^{x}}=32\)
- Solve \({{5}^{x}}\times {{3}^{2x-1}}=\frac{1}{135}\)
- Solve \({{5}^{3x-1}}=625\)
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Answer:(a) \(x=5\) (b) \(x=-1\) (c) \(\frac{5}{3}\)
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