Question 113983
Question 113983
Solve the cubic equation \(3{{x}^{3}}-13{{x}^{2}}+13x-3=0\). Hence, solve \(\frac{3}{8}{{y}^{3}}-\frac{13}{4}{{y}^{2}}+\frac{13}{2}y-3=0\)
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Answer:\(x=3,\frac{1}{3},1\); \(y=6,\frac{2}{3},2\)
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