The lengths of the two shorter sides of a right-angle triangle are \(\left( 2\sqrt{3}+\sqrt{15} \right)\mathrm{ cm}\) and \(\left( 6\sqrt{3}-2\sqrt{15} \right)\mathrm{ cm}\) respectively. Find the area of the triangle in the form \(\left( a+b\sqrt{c} \right)\mathrm{ c}{{\mathrm{m}}^{\mathrm{2}}}\).
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