Question 111693

Question 111693

Calculate the values of \(c\) for which \(2{{x}^{2}}-3x+c\) is always greater than \(-2\).
Find the range of values of \(m\) for which \({{x}^{2}}+mx+3m\) is always greater than \(8\) for all real values of \(x\).

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Answer:\(c>-\dfrac{7}{8}\); \(4<m<8\)

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