Polynomials, Cubic Equations and Partial Fractions - Factorisation by Special Identities
Polynomials, Cubic Equations and Partial Fractions - Factorisation by Special Identities
TGM Original Questions
Factorise \(16{{a}^{4}}-81{{b}^{6}}\) completely. Hence simplify \(\frac{16{{a}^{4}}-81{{b}^{6}}}{4{{a}^{2}}+9{{b}^{3}}}\).
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Answer:\(16a^4-81b^6=(4a^2+9b^3)(4a^2-9b^3)\). The fraction simplifies to \(4a^2-9b^3\), where \(4a^2+9b^3\ne0\).
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