Consider a two-digit number represented as $\left( 10x+y \right)$, where $x$ and $y$

Question

Consider a two-digit number represented as $\left( 10x+y \right)$, where $x$ and $y$ are positive integers and $x>y$. Reversing the digits gives a new number. Find values for $x$ and $y$ such that the difference between the squares of the two numbers is $1089$.

Accepted Answer

$x = 6, y = 5$

Polynomials, Cubic Equations and Partial Fractions - Linear and Non-Linear Simultaneous Equations

Polynomials, Cubic Equations and Partial Fractions - Linear and Non-Linear Simultaneous Equations

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