Disks about the Vertical Axis

Disks about the Vertical Axis

IB Year 6 | Grade 12
IB AA HL integration notes — 23 October 2026

A horizontal strip adjoining the vertical axis sweeps out a disk. Its radius is a horizontal distance, so express the radius in terms of \(y\).

\(V=\pi\int_c^d[\mathrm{g}(y)]^2\,\mathrm{d}y\), where \(x=\mathrm{g}(y)\).

Matching radius and variable

For the region between \(x=y^2\), the vertical axis and \(y=2\), the radius is \(y^2\), not \(y\).

\(V=\pi\int_0^2(y^2)^2\,\mathrm{d}y=\pi\left[\dfrac{y^5}{5}\right]_0^2=\dfrac{32\pi}{5}\).

Axis of rotationStripRadius squaredLimits
HorizontalVertical\(y^2\), expressed in \(x\)\(x\)-coordinates
VerticalHorizontal\(x^2\), expressed in \(y\)\(y\)-coordinates

When a square root appears in the curve equation, rearrange directly for \(x^2\) if possible. This often avoids unnecessary radicals.

On a calculator paper, keep an exact multiple of \(\pi\) when the question requests an exact answer.

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