A horizontal strip adjoining the vertical axis sweeps out a disk. Its radius is a horizontal distance, so express the radius in terms of \(y\).
\(V=\pi\int_c^d[\mathrm{g}(y)]^2\,\mathrm{d}y\), where \(x=\mathrm{g}(y)\).
For the region between \(x=y^2\), the vertical axis and \(y=2\), the radius is \(y^2\), not \(y\).
\(V=\pi\int_0^2(y^2)^2\,\mathrm{d}y=\pi\left[\dfrac{y^5}{5}\right]_0^2=\dfrac{32\pi}{5}\).
| Axis of rotation | Strip | Radius squared | Limits |
|---|---|---|---|
| Horizontal | Vertical | \(y^2\), expressed in \(x\) | \(x\)-coordinates |
| Vertical | Horizontal | \(x^2\), expressed in \(y\) | \(y\)-coordinates |
When a square root appears in the curve equation, rearrange directly for \(x^2\) if possible. This often avoids unnecessary radicals.
On a calculator paper, keep an exact multiple of \(\pi\) when the question requests an exact answer.
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