Parameter and tangency from a graph

Parameter and tangency from a graph

Secondary 2
8 marks
TGM Original Questions

Optional extension

The graph of \(y=x^2+4x+a\) shown has roots \(-5\) and \(1\).

  1. State its line of symmetry.[2]
  2. Find \(a\).[2]
  3. The line \(y=-8\) meets the graph twice; find the two points of intersection.[2]
  4. Find \(h\) such that \(x^2+4x-5=h\) has exactly one real solution.[2]

Solution:

Solution locked

Sign in to view the step-by-step solution

Please join our E Math programme to search for similar questions for more practice.

E Math Tuition
Answer:(a) \(x=-2\) (b) \(a=-5\) (c) \((-3,-8),(-1,-8)\) (d) \(h=-9\).

Need help? Join our JC Math tuition classes.

Learn more